A cornot engine has the same efficiency between (i) 100 K and 500 K and (ii) T and 900 K. Find T.

Answer

`ETA=T/900`

Explanation

`eta_(1) = 1 -(T_1)/(T_2) = 1-(1000)/(500) =(4)/(5)`
`eta_2 = 1-(T)/(900) rArr (T)/(900) = (1)/(5) rArr T=(1)/(5) = 180 K`