`3` moles of an ideal mono atomic gas performs a cycle as shown in fig. `If` gas temperature `T_(A)=400 K` `T_(B)=800K,T_(C)=2400K`, and `T_(D)=1200K`. Then total work done by gas is

Answer

20 KJ

Explanation

` W_(BC) = 3R(T_(C) -T_(B))`
`W_(AB) = W_(CD) = 0`
"because the processes are isochoric"
`W_(DA) = 3R (T_(A)-T_(D))`
`therefore Total work done`
`W_(BC) + W_(DA) = 3R(T_(A) + T_(C) -T_(B) -T_(D))`
`=3R(400 + 2400 - 800 - 1200)`
`=2400 R = 2kJ`