On mole of Argon is heated using `PV^3/2 =` constant. Find the amount of heat obtained by the process when the temperature changes by triangleT = -26 K.

Answer

108 J

Explanation

Let p the number of moles here p = 1
then C ` = (R)/(gamma -1) -(R)/(eta - 1) = (R)/((5)/(3)-1) - (R)/((3)/(2)-1)`
`triangleQ = pCtriangleT=1((3)/(2)R - 2R)(-26)`
`=+26((8.314)/(2))=108J`