As a result of heating a mole of an ideal gas at constant pressure by `72^(@)C`, a heat flow by an amount 1600 joules takes place. Find the work performed by the gas, the increment of its internal energy, and the value of `gamma`.
[Hint:`triangleQ = triangleU + triangleW`
or `C_(p) triangleT = C_(v)triangleT + triangleW`
or `triangleW = (C_p-C_v)triangleT=RtriangleT] h`

Answer

`597.6J,0.65^(@)C`

Explanation

`triangleQ = nC_(p)triangleT`
`triangleU = nC_(v) triangleT`
`triangleW = triangleQ - triangleU = n(C_(p)-C_(v))triangleT`
`1(R) triangleT`
`=8.3xx72 = 597.6 J`
`triangleU = 1600 - 597.6 = 1002.4 J`
`r=(C_(p))/(C_(v)) =(1600)/(1002.4)=5/3`