A volume of gas at atmospheric pressure is compressed adiabatically to half its original volume, Calculated the resulting pressure `(gamma= 1.4).(1 atmoshpere = 0.76 m of mercury)`

Answer

`2^(gamma)-1P_(1)` and `2^(gamma)-1T_2`

Explanation

`PV^(2) = constant`
`P_(1) = 1 atm p_(2) =?`
`V_(1) =V V_(2) =V/2 r=1.4`
`p_(1) = (0.76)m of hg`
`(0.76)(V)^(7//5) = P_(2)(V//2)^7//5`
`P_(2) = (0.76)(2)^7//5 = 2 m` of Hg`