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A mole of a monatimic perfect gas is adi...

A mole of a monatimic perfect gas is adiabatically comporessed when its temperature rises from `27^(@)` to `127^(@)C`. Calculate the work done.
[Hint: Work done `=R(T-T')/gamma-1,` for monatomic gas `= 5/3`]

Text Solution

Verified by Experts

`T =29^(@) rarr 127 ^(@)C`
`n=1 mole`
process adiabaltic
`triangleW =(P_(i)V_(i)-P_(f)V_(f))/(r-1) = nR(T_(i)-T_(f))/(r-1)`
` = (8.3(300-400))/(2//3)`
`=-100xx(8.3xx33)/(2)`
`=-1245 J`
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