Two moles of a certain gas at a temperature `T_0=300K` were cooled isochorically so that the pressure of the gas got reduced 2 times. Then as a result of isobaric process, the gas is allowed to expand till its temperature got back to the initial value. Find the total amount of heat absorbed by gas in this process.

Answer

`3.25xx10^(3J)`

Explanation

isochoric process
`(A)(P,V,T)rarr(B)((P)/(2),V,(T)/(2))rarr((P)/(2),V'T)`
`triangleQ =triangleQ_(1)+triangleQ_(2)`
`triangleQ_(1)=nC_(v)triangleT_(1)=2xx(FR)/(2)triangleT_(1)=FR((-T)/(2))`
`triangleQ_(2)=nC_(P)triangleT_(2)=2(((F+2)R)/(2))triangleT_(2)=(F+2)((T)/(2))`
`triangleQ=(FRT)/(2)+RT-FR(T)/(2)=RT`
`=8.3xx300=2.4xx10^(3)`jonles