The above p-v diagram represents the thermodynamic cycle of an engine, operating with an ideal monoatomic gas. The amount of heat, extracted from the source in a single cycle is

Options

A. `(13/(2)P_0V_0`
B. `(11)/(2)P_0V_0`
C. `4P_0V_0`
D. `P_0V_0`

Answer

A

Explanation

`Q_(given during isochoric & isobaric process)`
`Q_(1)=nCvtriangleT_1=3/2nRtriangleT_1=3/2P_0V_0`
`Q_2=nC_ptriangleT_(2)=(5)/(2)nRtriangleT_(2)=(5)/(2)xx2P_0V_0`
`Q=Q_1+Q_2=13/2P_0V_0`