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Given that vec(A)+vec(B)+vec(C )=vec(0)....

Given that `vec(A)+vec(B)+vec(C )=vec(0)`. Out of three vectors, two are equal in magnitude and the magnitude of the third vectors is `sqrt(2)` times that of either of the two having equal magnitude. Find the angles between the vectors.

A

`30^(@) ,60^(@),90^(@) " "`

B

`45^(@),45^(@),90^(@) " "`

C

`45^(@),60^(@),90^(@) " "`

D

`90^(@),135^(@) ,135^(@)`

Text Solution

Verified by Experts

The correct Answer is:
D
(D) From polygon law, there vectors having summation zero, should form a closed polygon (triangle). Since the two vectors are having same magnitude and the third vector is `sqrt(2)` times that of either of two having equal magnitude. i.e. the triangle should be right angled triangle.

Angle between A and B `90^(@)`
Angle between B and C is `135^(@)`
Angle between A and C is `135^(@)`
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Knowledge Check

  • given that vecA+vecB+vecC=0 out of three vectors two are equal in magnitude and the magnitude of third vector is sqrt2 times that of either of the two having equal magnitude. Then the angles between vectors are given by

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