The angle subtended by the moon's diameter at a point on the earth is about `0.50^(@)` . Use this and the fact that the moon is about 384000km away to find the approximate diameter of the moon .

Explanation

`tan theta ~=theta=(D)/(r_(m))theta ` is radians
`180^(@)=pi-radians`
`rArr" " 0.5^(@)=(pi)/(180)xx(1)/(2)rad=(pi)/(360)rad`
`rArr" " D=theta.r_(m)`
`=(pi)/(360)xx384000km=3350km`