Home
Class 11
PHYSICS
A boy is pulling a block by a force of 1...

A boy is pulling a block by a force of `10 N` at an angle of `37^(@)` to the horizontal .
` )`

A

The component of this force in the horizontal direction is `6N`

B

The component of this force in the horizontal direction is `8N`

C

The component of the force in the vertical direction in `6N`

D

The component of this force in the vertical direction is `8N`

Text Solution

Verified by Experts

The correct Answer is:
B, C
Horizontal component `=10 cos 37^(@)=8N` ltbr) Vertical component `=10 sin 37^(@)=6N`
Promotional Banner

Topper's Solved these Questions

  • UNIT DIMENSION, VECTOR & BASIC MATHS

    BANSAL|Exercise EXERCISE - 2 [MATRIX TYPE]|1 Videos

  • UNIT DIMENSION, VECTOR & BASIC MATHS

    BANSAL|Exercise EXERCISE - 3 (Miscellaneous Exercise)|20 Videos

  • UNIT DIMENSION, VECTOR & BASIC MATHS

    BANSAL|Exercise EXERCISE - 1 [SINGLE CORRECT CHOICE TYPE]|34 Videos

  • KINETIC THEORY OF GASES

    BANSAL|Exercise Section-B|13 Videos

Similar Questions

Explore conceptually related problems

A child pulls a box with a force of 200 N at an angle of 60^(@) above the horizontal. Then the horizontal and vertical components of the force are-

A block of mass 5 kg is (i) pushed in case (A) and (ii) pulled in case (B), by a force F = 20 N, making an angle of 30^(@) with the horizontal, as shown in the figures. The coefficient of friction between the block and floor is mu=0.2 . The difference between the accelerations of the block, in case (B) and case (A) will be: (g=10ms^(-2))

A block of mass m = 10 kg is pulled by a force F = 100 N at an angle theta=30^(@) with the horizontal along a smooth horizontal surface. What is the acceleration of the block? (g = 10m//s^(2))

A boy pushes a toy box 2.0 m along the floor by means of a force of 10 N directed downward at an angle of 60^(@) to the horizontal.The work done by the boy is

A block of weight 200N is pulled along a rough horizontal surface at contant speed by a force of 100N acting at an angle 30^(@) above the horizontal. The coefficient of kinetic friction between the block and the surface is .

A block of mass m is placed on a horizontla surface. If the block is pulled by applying a force of magnitude F=5mg at an angle theta=37^(@) , with horizontal as shown in fig. find the acceleration of the block at the given instant.

A 3kg block is pulled byh a force which I sinclined at 37^(@) to the horizontal table. The friction coefficient between the table and block is 1//3 . For what minimum value of this force, will the block start sliding?

A block of mass m = 3 kg is resting over a rough horizontal surface having coefficient of friction mu = 1//3 The block is pulled to the right by appliying a force F inclined at angle 37^(@) with the horizontal as shown in fig .The forceincreases with time according to law F = 2r newton Calculate its velocity v at t = 10s (g = 10 ms^(-2))

A rectangular block of mass 5 kg is kept on a horizontal surface . The coefficient of friction between the block and the surface is 0.2 . If a force of 20 N is applied to the block at angle of 30^(@) with the horizontal plane , what is the force of friction on the block ? (Take g = 10 m//s^(2) )