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If a body is rotating such that its angl...

If a body is rotating such that its angle from a fixed location is given by `theta=t^(3)-3t^(2)-6t+3` . Find its angular velocity, angular acceleration, and the time at which its angular velocity is zero.

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The correct Answer is:
`3t^(2)-6t-6 ` rad//sec, `6t-6` rad//sec^(2), 1+sqrt(3)`sec
`omega=(d theta)/(dt)=3t^(2)-6t-6`
`alpha =(d omega)/(dt)=6t-6`
`omega=0 rArr3t^(2)-6t-6=0`
`t^(2)-2t-2=0`
`t(2+-sqrt(4+8))/(2)`
`t=(2+-sqrt(12))/(2)`
`t=1+sqrt(3) sec`
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