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If velocity of a particle is given by `v=3t^(2)-6t +4`. Find its displacement from `t=0` to `3 secs`.

Text Solution

Verified by Experts

The correct Answer is:
`12m`

(i) ` underset(x_(1))overset(x_(2))intdx=underset(0)overset(3)int(3t^(2)-6t+4)dt`
`"displacement"=(t^(3)-3t^(2)+4t)_(0)^(3)=27-27+12m=12m`
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