The velocity-time graph of a linear motion is shown below. Find the (a) displacement and distance from the origin after `8s`. (b) acceleration in the first second. (c) deceleration during the `5^(th)` second. (d) maximum speed during the motion.

Answer

(a) `6am, 18m` (b) `4m//s^(2)` (c) `-2m//s^(2)` (d)`4m//s`

Explanation

(a) `"Displacement"=(1)/(2)(4+2)4-(1)/(2)(4+2)2=12-6=6m`
` "Distance" =|(1)/(2)(4+2)4|+|-(1)/(2)(4+2)2|=12+6=18m`
(b) `a=(4)/(1)=4m//s^(2)`
(c) `a=-(2)/(1)=-2m//s^(2)`
(d)`v=4m//s)`