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Two vehicles are horning at (320)/(3) ...

Two vehicles are horning at `(320)/(3)` Hz. They are moving directly towards each other. A is moving at 10 m/s and B is moving such that he hears a beat frequency of 5 Hz at t = 0. If they are 90 m apart at t = 0, at what time (in sec) vehicles cross each other ? (Take speed of sound = 330 m/s)

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The correct Answer is:
`6.00`

`5=(320)/(3)[(330+v_(0))/(330-10)]-(320)/(3)rArr v_(0)=5 m//s`
`therefore = (90)/(15)= 6 sec`
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