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A circular coil of radius 0.1 m and 100 ...

A circular coil of radius 0.1 m and 100 turns placed invertical plane, which is perpendicular to magnitic meridian. When current of 2A is flow through the coil then the neutral point is obtained at the centre, then horizontal component of earth magnetic field at the place will be `N_(pi)xx10^(-N)T` then N will be :-

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Verified by Experts

The correct Answer is:
`4.00`
`B=B_(H)`
`(mu_(0)N_(i))/(2r)=N_(H)`
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