A conducting rod of 1 m length and 1 kg mass is suspended by two vertical wires through its ends. An external magnetic field of 2T is applied normal to the rod. Now, the current to be passed through the rod so as to make the tension in the wires zero is : (Take `g = 10 ms^(-2)`) :

Answer

`5.00`

Explanation

`U_(av)=(B_(0)^(2))/(4mu_(0))=(1)/(4)in_(0)E_(0)^(2)`