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Find the solution of sinx=-(sqrt(3))/2....

Find the solution of `sinx=-(sqrt(3))/2`.

Text Solution

Verified by Experts

The correct Answer is:
`x = n pi + (-1)^n ((4 pi)/3), n in mathbbZ`
`sinx=-(sqrt(3))/2`
`=-sin(pi/3)`
`=sin(pi + pi/3)`
`=sin((4 pi)/3)`
`implies x = n pi + (-1)^n ((4 pi)/3), \ \ n in mathbbZ`
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Knowledge Check

  • The principal solution of sinx=-(sqrt(3))/(2) is

    A
    `(pi)/(3)`
    B
    `(4pi)/(3)`
    C
    `(2pi)/(3)`
    D
    `-(4pi)/(3)`

  • General solution of sinx=(sqrt(3))/(2) is

    A
    `npi+(-1)^(n)(pi)/(3), ninZ`
    B
    `2npi+(-1)^(n)(pi)/(3), ninZ`
    C
    `npi+(-1)^(n-1)(pi)/(3), ninZ`
    D
    `npi+(-1)^(n+1)(pi)/(3), ninZ`

  • General solution of sinx=(-sqrt(3))/(2) is

    A
    `npi+(-1)^(n)(pi)/(3), ninZ`
    B
    `npi+(-1)^(n)(5pi)/(3), ninZ`
    C
    `npi+(-1)^(n)(7pi)/(3), ninZ`
    D
    `npi+(-1)^(n)(4pi)/(3), ninZ`