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A parallel plate capacitor of plate area...

A parallel plate capacitor of plate area A and plate separation d is charged to a potential difference V and then the battery is disconnected. A slab of dielectric constant k is then inserted between the plates of the capacitor so as to fill the space between the plates. If Q, E and W denote respectively the charge on each plate, the electric field between the plates and the work done in the process of inserting the slab, then

A

`Q=(in_0AV)/(d)`

B

`Q=(in_0 kAV)/(d)`

C

`E=(V)/(kd)`

D

`W=(in_0 AV^2)/(2d)(1-(1)/(k))`

Text Solution

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The correct Answer is:
A, C, D
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