What is the magnetic field produced at the centre of a hydrogen atom due to revolution of its electron in the first order (K-orbit).
Radius of the first orbit `=0.53xx10^(-10)m`, velocity of electron in that orbit `=2.19xx10^(6) m*s^(-1)`.

Explanation

Time period of revolution, `T=(2pir)/(v)`.
So, the circular loop formed due to revolution of the electron carries an effective current,
`I=("charge")/("time period")=(e)/(T)=(ev)/(2pir)`
So, magnetic field at the cenrte of the atom,
`B=(mu_(0)I)/(2r)=(mu_(0))/(4pi)*(ev)/(r^(2))`
`=10^(-7)xx((1.6xx10^(-19))xx(2.19xx10^(6)))/((0.53xx10^(-10))^(2))=12.47T`