A particle with charge q moves with velocity `vecv` in a direction perpendicular to the magnetic field lines. What would be the direction of force experienced by the particle ? What is the nature of the path described by the particle ? Find the cyclotron Frequency.

A charge q moves with velocity vecv at an angle theta to a magnetic field vecB . What is the force experienced by the particle?

A particle with charge q is moving with a velocity vecv in a magnetic field vecB . If the force acting on the particle is vecF then,

A proton enters a magnetic field vecB with velocity vecV in a direction opposite to vecB .The net magnetic force is—

An electron having charge e moves with velocity vecv in +x direction. An electric field acts on it along +y direction. The force on the electron acts along-

A particle having q enters a magnetic field with a velocity vecv in the direction normal to the field. Determine the radius of the circular path described by the particle and its frequency of rotation.

A particle of mass 'm' and carrying a charge q enters with a velocity 'v' perpendicular to a uniform magnetic field. The time period of rotation of the particle

A particle of charge q moves with a velocity vecv=ahati+bhatj in magnetic field vecB=chati+dhatj . The force acting on the particle has magnitude F. Them

The path of a charged particle whose motion is perpendicular to a uniform magnetic field is

A charged particle moving in a straight line perpendicular to a uniform magnetic field enters the field. What will be its path in the field?

A particle with charge q moves with a velocity V in a direction perpendicular to the directions of uniform electric and magnetic fields, E and B respectively, which are mutually perpendicular to each other. Which one of the following gives the condition for which the particle moves undeflected in its original trajectory ?