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A charged particle is released from rest in a region of steady and uniform electric and magnetic fields, which are parallel to each other. What will be the nature of the path followed by the charged aprticle ?

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The force on a particel of charge q and mass m acting along the direction of the uniform electric field `vecE=eE`, and its acceleration `=(qE)/(m)`= constant. So, this particle has a uniformly accelerated motion along `vecE`.
Now, `vecE and vecB` are parallel, thus the particle velocity is also parallel to `vecB`. then, the magnetic force on the particle =0, i.e., the magnetic field has no effect on the motion of the particle.
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