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Two indentical current carrying coaxial ...

Two indentical current carrying coaxial loops, carry current I in an opposite sense. A simple amperian loop passes through both of then once. Calling the loop as C,

A

`oint_(C) vecB*dvecl= pm2 mu_(0)I`

B

the value of `oint_(C) vecB*dvecl` is independent of the shape of C

C

there may bea point on c where `vecB and d vecl` are perpendicular

D

`vecB` vanishes everywhere on C

Text Solution

Verified by Experts

The correct Answer is:
B, C
`oint_(C) vecB*dvecl= mu_(0)(I-I)=0 [ :. oint_(C) vecB*dvecl=mu_(0)I]`
At the two extremeties of C, `vecB and dvecl` are perpendicular to each other.
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