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A rod of length 10 cm lies along the pri...

A rod of length 10 cm lies along the principal axis of a concave mirror of focal length 10 cm in such a way that its end closer to the pole is 20 cm away from the mirror? What is the length of the image?

Text Solution

Verified by Experts

`"Here for the side" A, f=-10 cm , u =- 20 cm.`
`"from the equation", (1)/(u)+(1)/(v)=(1)/(f) "we get", v=-20 cm `
For the side B, u = -30 cm
Similarly, v = -15 cm
`therefore` Length of the image = 20 -15 = 5cm
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