Use the mirror equation to deduce that :
the virtual image produced by a convex mirror is always diminished in size and is located between the focus and the pole

Explanation

In case of a concave mirror,
`(1)/(f) = (1)/(v) + (1)/(u)`
`or, (u)/(v) = (u)/(f) - 1`
`or, -(1)/(m) = (u-f)/(f)`
`or, -m = (f)/(u-f)`
`therefore " " m=(f)/(f-u)`
`therefore "In this case u is - ve and f is + ve , " f-u gt f.`
`therefore m lt 1 i.e., "the image is diminished."`