The magnifying power of an astronomical ...

The magnifying power of an astronomical telescope for normal vision is 10 . The focal length of the objective is 20 cm . What will be the magnifying power for focussing the final image formed at a distance of 25 cm from the eyepiece ?

Text Solution

Verified by Experts

The correct Answer is:

18.8

Topper's Solved these Questions

OPTICAL INSTRUMENTS
CHHAYA PUBLICATION|Exercise Problem Set -II|6 Videos
OPTICAL INSTRUMENTS
CHHAYA PUBLICATION|Exercise Problem Set -II ( Hots Numerical Problems )|8 Videos
OPTICAL INSTRUMENTS
CHHAYA PUBLICATION|Exercise Exercise (short Answer Type Questions-I)|1 Videos
Magnetic Properties of Materials
CHHAYA PUBLICATION|Exercise CBSE SCANNER|11 Videos
QUANTUM THEORY
CHHAYA PUBLICATION|Exercise CBSE Scanner|29 Videos

Similar Questions

Explore conceptually related problems

If the focal length of objective lens is increased then magnifying power of the

The magnifying power of a telescope in normal adjustment is 20 , and the focal length of the eyepiece is 5xx10^(-2) m. what is the magnifying power obtained when the system is adjusted so that the final image of a distant object is formed 25xx10^(-2) m away from the eyepiece?

The lengths of a compound telescope is 21.5 cm . The focal lengths of its objective and eyepiece are 1.6 cm and 2.1 cm respectively . If the final image is formed at a distance of 22.45 cm from the eyepiece , then calculate the distance of the object from the objective.

If the focal length of the eye piece of a telescope is doubled, its magnifying power (m ) will be

The lengths of the tube of an astronomical telescope is 44 cm and its angular magnification is 10 . What is the focal length of its objective ?

A telescope is such that the power of its two lenses be 0.5D and 20D respectively. What will be the magnifying power of that lens? —

The focal lengths of the objective and the eyepiece of an astronomical telescope are 140 cm and 5 cm respectively. The magnifying power of the telescope for viewing objects when the final image is formed at the least distance of distinct vision (25 cm ) will be

A small astronomical telescope has an objective of focal length 50 cm and an eyepiece of focal length 5 cm . It is focussed at the sun and the final image is formed at a distance of 25 cm from the eyepiece . If the diameter of the sun subtends an angle of 32' at the centre of the objective calculate the angular magnification of the instrument and the actual size of the image.

CHHAYA PUBLICATION-OPTICAL INSTRUMENTS-Problem Set -I

A shortsighted man can read the writings of a book keeping it at a dis...
Text Solution
|
A man uses spectacles of a concave lens for his defective eye and can...
Text Solution
|
By using the spectacles of a concave lens of power -5 m^(-1) a man can...
Text Solution
|
A boy can see the objects distinctly only in between 15 cm and 200 cm ...
Text Solution
|
The near point of a man is at a distance of 200 cm from his eyes. Wha...
Text Solution
|
The far point of a myopic (short-sighted ) person is 80 cm in front of...
Text Solution
|
The near point of a hypermetropic (long -sighted ) person is 75 cm fro...
Text Solution
|
The least distance of distinct vision of a man is 1m . What type of ey...
Text Solution
|
The focal lengths fo the lens of a simple microscope is 5 cm . If the ...
Text Solution
|
Two lenses having power +15 m ^(-1) and +5 m^(-1) are placed in conta...
Text Solution
|
Two convex lenses of focal length 1.5 cm and 9 cm are arranged to for...
Text Solution
|
The focal lengths of the objective and the eyepiece of a compound micr...
Text Solution
|
The focal lenghts of the objective and the eyepiece of a compound micr...
Text Solution
|
The focal of the objective and the eyepiece of a compound microscope ...
Text Solution
|
The length of the tube of an astronomical telescope is 80 cm and the ...
Text Solution
|
The magnifying power of an astronomical telescope for normal vision is...
Text Solution
|