In a microwave over the electromagnetic waves are generated having wavelength of the order of 1 cm. Find the energy of the microwave photon. `(h = 6.33 xx 10^(-34) J.s)`.

Explanation

`lamda = 1 cm = 10^(-2) m, c = 3 xx 10^(8) m.s^(-1)`
`:. E = hf = (hc)/(lamda) = ((6.63 xx 10^(-34)) xx (3 xx 10^(8)))/(10^(-2))`
`= 1.989 xx 10^(-23) J = (1.989 xx 10^(-23))/(1.6 xx 10^(-19)) eV = 1.24 xx 10^(-4) eV`