A proton and an electron have the same kinetic energy. Which one has large de Broglie wavelength?

Explanation

de Broglie wavelength, `lamda = (h)/(sqrt(2mK))`
Since h and K are constants, `lamda prop (1)/(sqrt(m))`
If `m_(e) and m_(p)` be the masses of an electron and a proton respectively,
Then, `(lamda_(e))/(lamda_(p)) = sqrt((m_(p))/(m_(e))) gt 1`
`:. lamda_(e) gt lamda_(p)`
So, de Broglie wavelength of electron is greater.