What is the de Broglie wavelength of anitrogen molecule at 300 K? Assume the molecule to be moving with its rms speed. [Atomic mass of nitrogen = 14.0076 u ]

Explanation

`v_("rms") = sqrt((3kT)/(m))`
`:.` de Broglie wavelength of nitrogen molecule,
`lamda = (h)/(mv_("rms")) = (h)/(sqrt(3mkT))`
`= (6.626 xx 10^(-34))/((3 xx 28.0152 xx 1.38 xx 10^(-23) xx 300)^(1//2))`
`= 0.275 xx 10^(-10)m`