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An electron is accelerated by a photenti...

An electron is accelerated by a photential difference V and as a result, its de Broglie wavelength beocmes `lamda`. If the applied potential difference was 2V, the de Broglie wavelength would have been

A

`2 lamda`

B

`sqrt2 lamda`

C

`(lamda)/(sqrt2)`

D

`(lamda)/(2)`

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The correct Answer is:
C
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CHHAYA PUBLICATION-QUANTUM THEORY-Exercise (Multiple Choice Questions)
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