In spite of being a massless particle, a photon has some momentum-explain.

Boron halides in spite of being electron deficient do not exist as dimer-Explain.

An alpha -particle and a proton having same momentum ente into a region of uniform magnetic filed and paths r_a/r_p in the field is-

Einstein established the idea of photons on the basis of Planck's quantum theory. According to his idea, the light of frequency f or wavelength lamda is infact a stream of photons. The rest mass of each photon is zero and velocity is equal to the velocity of light (c) = 3 xx 10^(8) m.s^(-1) . Energy, E = hf, where h = Planck's constant = 6.625 xx 10^(-34)J.s . Each photon has a momentum p = (hf)/(c) , although its rest mass is zero. The number of photons increase when the intensity of incident light increases and vice-versa. On the other hand, according to de Broglie any stream of moving particles may be represented by progressive waves. The wavelength of the wave (de Broglie wavelength) is lamda = (h)/(p) , where p is the momentum of the particle. When a particle having charge e is accelerated with a potential difference of V, the kinetic energy gained by the particle is K= eV. Thus as the applied potential difference is increased, the kinetic energy of the particle and hence the momentum increase resulting in a decrease in the de Broglie wavelength. Given, charge of electron, e = 1.6 xx 10^(-19)C and mass = 9.1 xx 10^(-31) kg . The number of photons emitted per second by a source of light of power 30 W is 10^(20) , the momentum of each photon (in kg.m.s^(-1) )

Draw the curve showing the variation of de-Brogli wavelength of a particle with its momentum. Find the momentum of a photon of wavelength 1000 nm.

Draw the curve showing the variation of de Broglie wavelength of a particle with its momentum. Find the momentum of a photon of wavelength 0.01 Å

A particle performs uniform circular motion with an angular momentum L,. If the frequency of the particle motion is doubled the angular momentum becomes

Calculate the uncertainty in the position of a particle when the uncertainty in momentum is zero

The colloidal particles display Brownian movement but the particles of the suspension do not-explain.