A strong red ligh cannot be emit photoelectrons from a metal surface, yet a feeble ultraviolet radiation can - explain how it is possible.

Light rays of wavelength lambda and lambda/2 are incident on a a photosensitive metal surface, IF the maximum kinetic energy of the emitted photoelectrons from the metal surface in 2nd case be 3 times the maximum kinetic energy of emitted photoelectrons in the 1st case then determine the work function of the metal.

Write down Einstein's photoelectric equation and mention the symbols used. The photoelectric threshold wavelength for a certain metal is 400 nm. Find the maximum kinetic energy of the emitted electrons from the metal surface by ultraviolet light of wavelength 200 nm. Given, h= 6.63 xx 10^(-34) J.s

Write down Einstein's photoelectric equation and mention the symbols used. The photoelectric threshold wavelength for a certain metal as 400mm. Find the maximum kinetic enrgy of the emitted electrons from the metal surface by ultraviolet light of wavelength 200nm. Given h=6.63xx10^34

Statement I: Any light wave having frequency less than 4.8 xx 10^(14)Hz cannot emit photoelectrons from a metal surface having work function 2.0 eV Statement II: If the work function of a metal is W_(0) (in eV), then the maximum wavelength (in Å ) of the light capable of initiating photoelectric effect in the metal is given by lamda_("max") = (12400)/(W_(0))

Threshold wavelength for photoelectric emission from a metal surface is 3800Å , Utraviolet light of wave-length 2600Å is incident on the metal surface. maximum kinetic energy of emitted photoelectron. (h = 6.63 xx 10^(-27) " erg.s")

Electrons are emitted with zero velocity from a metal surface when it is exposed to radiation of wavelength 6800 Å. Calculate threshold frequency (v_(0)) and work function (W_(0)) of the metal.

Maximum kinetic energies of photoelectrons emitted from a metal surface when illuminated by radiations of wavelengths lamda_(1) and lamda_(2), " are " K_(1) and K_(2) , respectively. If lamda_(1) = 3 lamda_(2) , show that, K_(1) lt (K_(2))/(3)

When the energy of the incident radiation is increased by 20%, the kinetic energy of the photoelectrons emitted from a metal surface increased from 0.5eV to 0.8eV. The work function of the metal is

Statement I: The maximum velocity of the photoelectron emitted from a metal surface does not increase even if the intensity of the incident electromagnetic wave is increased. Statement II: Einstein's photoelectric equation: (1)/(2) mv_("max")^(2) = hf - W_(0)