An electromagnetic wave of wavelength `lamda` is incident on a photoelectrons emitted from this surface have the de Broglie wavelength `lamda_(1)` prove that `lamda = ((2mc)/(h)) lamda_(1)^(2)`

Radiation of wavelength lamda is incident on a photocell. The fastest emitted electron has speed v. If the wavelength is charged to (3lamda)/(4) , the speed of the fastest emitted electron will be

Show that the de Broglie wavelength of electron of energy K is given by lamda = (h)/(sqrt(2mK)) .

If two particles are associated with same kinetic energy, then the de Broglie's wavelength (lamda) of these particles is-

Maximum kinetic energies of photoelectrons emitted from a metal surface when illuminated by radiations of wavelengths lamda_(1) and lamda_(2), " are " K_(1) and K_(2) , respectively. If lamda_(1) = 3 lamda_(2) , show that, K_(1) lt (K_(2))/(3)

A monochromatic radiation of wavelength lamda and intensity I is incident on a plate of area A. Find the number of photons striking the plate per second.

Two moving electrons have a ratio of 1 : 2 between their respective kinetic energies. The ratio between their de Broglie wavelength is

A certain, metallic surface is illuminated with monochromatic light of wavelength, lamda . The stopping potential for photoelectric current for this light is 3 V_(0) . If the same surface is illuminated with light of wavelength 2lamda , the stopping potential is V_(0) . The threshold wavelength for this surface for photoelectric effect is

When a piece of metal is illuminated by monochromatic light of wavelength lamda , the stopping potential for photoelectric current is 2.5V_(0) . If the same surface is illuminated by light of wavelength 1.5 lamda , the stopping potential becomes V_(0) . Find the out the value of threshold wavelength for photoelectric emission.

The wavelength of an electromagnetic radiation is lamda . What is the energy of a photon of this radiation?

Work function of a metal surface is 2eV. Maximum kinetic energy of photoelectrons emitted from the surface for incidence of light of wavelength 4140 Å is 1eV. What is the threshold wavelength of radiation for that surface?