An electron of mass m and a photon have same energy E. The ratio of de Broglie wavelength associated with them is

Options

A. `((E)/(2m))^(1//2)`
B. `c(2mE)^(1//2)`
C. `(1)/(c) ((2m)/(E))^(1//2)`
D. `(1)/(c) ((E)/(2m))^(1//2)`

Answer

D

Explanation

de Broglie wavelength of electron, `lamda_(e) = (h)/(p) = (h)/(sqrt(2mE))`
de Broglie wavelength of photon, `lamda_(p) = (hc)/(E)`
`:. (lamda_(e))/(lamda_(p)) = (h)/(sqrt(2mE)) xx (E)/(hc) = (1)/(c) sqrt((E)/(2m))`