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If the mass of neutron is 1.7xx10^(-27) ...

If the mass of neutron is `1.7xx10^(-27) kg`, then the de Broglie wavelength of neutron of energy 3eV is `(h = 6.6xx10^(-34) J.s)`

A

`1.4 xx 10^(-11) m`

B

`1.6 xx 10^(-10)m`

C

`1.65 xx 10^(-11) m`

D

`1.4 xx 10^(-10)m`

Text Solution

Verified by Experts

The correct Answer is:
C
`lamda = (h)/(p) = (h)/(sqrt(2mE))`
`= (6.6 xx 10^(-34))/(sqrt([2 xx (1.7 xx 10^(-19))]))`
`= 1.634 xx 10^(-11) m`
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