Explain giving reasons for the following:
The stopping potential `(V^(0))` varies linearly with the frequency (v) of the incident radiation for a given photosensitive surface with the slope remaining the same for different surfaces.

Explain giving reasons for the following: Photoelectric current in a photocell increase with the increase in the intensity of the incident radiation.

The stopping potential for photoelectrons from a metal surface is V_(1) when monochromatic light of frequency v_(1) is incident on it. The stopping potential becomes V_(2) when monochromatic light of another frequency is incident on the same metal surface. If h be the Planck's constant and e be the charge of an electron, then the frequency of light in the second case is

When a metallic surface is illuminated with radiation of wavelength lamda , the stopping poential is V. If the same surface is illuminated with radiation of wavelength 2lamda , the stopping potential is V/4 . The threshold wavelength for the metallic surface is

When radiation of wavelength lamda is incidenton a metallic surface, the stopping potential is 4.8V. If the same surface is illuminated with radiation of double the wavelength, the stopping potential becomes 1.6V. What is the threshold wavelength for the surface?

The threshold frequency of photoelectric effect of a metal surface is f_(0) . The stopping potentials are V_(0) and nV_(0) when the frequencies of incident light are 2f_(0) and 4f_(0) . What is the value of n ?

For a metal surface, ratio of the stopping potentials for two different frequencies of incident lights is 1 : 4 , what is the ratio of the maximum velocities in the two cases?

For a monochromatic radiation incident on a metal surface, the stopping potential is 2.0V. Find out the maximum velocity of the emitted photoelectrons.

For a monochromatic light incident on a metal surface, the stopping potential is V. Then the kinetic energy of the fastest photoelectrons emitted from that surface is

When light of frequency v_(1) is incident on a metal with work function W (where hv_(1) gt W ) the photocurrent falls to zero at a stopping potential of V_(1) . If the frequency of light is increased to v_(2) , the stopping potential changes to V_(2) . Therefore the charge of an electron is given by

When the light of frequency 2v_(0) (where v_(0) is threshold frequency) is incident on a metal plate, the maximum velocity of electrons emitted is v_(01) . When the frequency of the incident radiation is increased to 5 v_(0) , the maximum velocity of electrons emitted from the same plate is v_(2) . The ratio of v_(1) to v_(2) is