What minimum terminal potential difference of a Coolidge tube should be maintained to produce X -ray of wavelength 0.8 Å ? `[h=6.62xx10^(-34)J*s,e=1.60xx10^(-19) C,c=3xx10^8m*s ^(-1)]`

Explanation

Energy of X -ray photon,
E`=(hc)/(lambda)[ "here" ,lambda= 0.8"Å"=0.8xx10^(-10)m]`
If electrons be accelerated in a X-ray tube by a potential difference V , energy of an electron =eV, if this energy is completely converted into the energy of X-ray photon, the value of V will be the minimum .
So, `eV_(max) =(hc)/(lambda)`
or, `V_(max) =(hc)/(elambda)=(6.62xx10^(-34)xx3xx10^(8))/(1.60xx10^(-19)xx0.8xx10^(-10))=15516V`