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Find out the wavelength of the electron orbiting in the ground state of hydrogen atom.

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The wavelength of the electron orbiting in the ground state of hydrogen atom,
`lambda=(hc)/E=(6.62xx10^(-34)xx3xx10^(8))/(13.6 eV)`
(ground state energy of hydrogen atom =13.6 eV)
`=(6.62xx10^(-34)xx3xx10^(8))/(13.6xx1.6xx10^(-19))`
`=9.126xx10^(-8)m =912.6 "Å"`
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