In a rocket of mass 1000 kg fuel is consumed at a rate of 40 kg/s . The velocity of the gases ejected from the rocket is `5xx10^(4)m//s`. The thrust on the rocket is

Options

A. `2xx10^(3)N`
B. `5xx10^(4)N`
C. `2xx10^(6)N`
D. `2xx10^(9)N`

Answer

To find the thrust on the rocket, we can use the formula for thrust, which is given by:

\[ \text{Thrust} = \text{mass flow rate} \times \text{velocity of the ejected gases} \]

### Step-by-step Solution:

1. **Identify the mass flow rate**:
The mass flow rate of the fuel is given as \( 40 \, \text{kg/s} \).

2. **Identify the velocity of the ejected gases**:
The velocity of the gases ejected from the rocket is given as \( 5 \times 10^4 \, \text{m/s} \).

3. **Substitute the values into the thrust formula**:
\[ \text{Thrust} = 40 \, \text{kg/s} \times 5 \times 10^4 \, \text{m/s} \]

4. **Calculate the thrust**:
\[ \text{Thrust} = 40 \times 5 \times 10^4 = 200 \times 10^4 \, \text{N} \]

5. **Express in standard form**:
\[ 200 \times 10^4 \, \text{N} = 2 \times 10^6 \, \text{N} \]

### Final Answer:
The thrust on the rocket is \( 2 \times 10^6 \, \text{N} \).