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Ammoina dissociates into N(2) and H(2) s...

Ammoina dissociates into `N_(2)` and `H_(2)` such that degree of dissociation `alpha` is very less than 1 and equilibrium pressure is `P_(0)` then the value of `alpha` is [if `K_(p)` for `2NH_(3)(g)hArrN_(2)(g) + 3H_(2)(g) + 3H_(2)(g)` is `27xx10^(-8)P_(0)^(2)]` :

A

`10^(-4)`

B

`4xx10^(-4)`

C

`0.02`

D

can't be calculated

Text Solution

Verified by Experts

The correct Answer is:
C
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