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A flask is initially filled with pure N2...

A flask is initially filled with pure `N_2O_3(g)` having pressure 2 bar and following equilibria are established.
`N_2O_3(g)hArrNO_2(g)+NO(g)" "K_(P_1)=2.5bar`
`2NO_2(g)hArrN_2O_4(g)" "K_(P_2)=?`
If at equilibrium partial pressure of NO(g) was found to be 1.5 bar,then:

A

Equilibrium parial pressure of `N_2O_3(g)` is 0.5 bar.

B

Equilibrium partial pressure of `NO_2(g)` is 0.83 bar.

C

Equilibrium parital pressure of `N_2O_4` is 0.33 bar.

D

Value of `K_(P_2)` is 0.48 bar

Text Solution

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The correct Answer is:
A, B, C, D
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