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Potential energy of electron present in ...

Potential energy of electron present in 2nd orbit of `Li^(2+)` is :(`r_(0)` = Radius of 1st Bohr's orbit )

A

`(e^(2))/(4pi in_(0) r_(0))`

B

`-(3e^(2))/(4pi in_(0) r_(0))`

C

`-(3e^(2))/(16pi in_(0) r_(0))`

D

`-(9e^(2))/(16pi in_(0) r_(0))`

Text Solution

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The correct Answer is:
C
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