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For an orbital , Psi(300) = (1)/(81sqr...

For an orbital ,
`Psi_(300) = (1)/(81sqrt3 pi) ((z)/(a_(0)))^(3//2)[27 - 18u + 2u^(2)]"exp" ((-u)/(3))` where `u = (zr)/(a_(0))`
What is the maximum radial distance of node from nucleus of `He^(+)` ion ?

A

`(3 + sqrt3) (3a_(0))/(2)`

B

`(3 + sqrt3) (3a_(0))/(4)`

C

`a_(0)`

D

`(a_(0))/(2)`

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The correct Answer is:
B
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According to qauntum mechanical model of H-like species, and electron can be represented by a wave function (psi) which contain all dynamic information about the electron. The nature of wave function depends on the type of the orbital to which the electron belongs. For an orbital psi=[sqrt(2)/(81sqrt(3pi))]((1)/(a_(0)))^(3//2)(27-18sigma+2sigma^(2))e^((sigma)/(3)) Where, sigma =((Zr)/(a_(0))),r = radial distance from nucleous, a_(0)=52.9"pm" The number of radial and angular nodes possible for the orbital given above are respectively

According to qauntum mechanical model of H-like species, and electron can be represented by a wave function (psi) which contain all dynamic information about the electron. The nature of wave function depends on the type of the orbital to which the electron belongs. For an orbital psi=[sqrt(2)/(81sqrt(3pi))]((1)/(a_(0)))^(3//2)(27-18sigma+2sigma^(2))e^((sigma)/(3)) Where, sigma =((Zr)/(a_(0))),r = radial distance from nucleous, a_(0)=52.9pm Which of the following represents the position of one of the radial nodes?

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The Schrodinger wave equation for hydrogen atom of 4s- orbital is given by : Psi (r) = (1)/(16sqrt4)((1)/(a_(0)))^(3//2)[(sigma^(2) - 1)(sigma^(2) - 8 sigma + 12)]e^(-sigma//2) where a_(0) = 1^(st) Bohr radius and sigma = (2r)/(a_(0)) . The distance from the nucleus where there will be no radial node will be :

The Schrodinger wave equation for hydrogen atom is Psi_(2s) = (1)/(4sqrt(2pi)) ((1)/(a_(0)))^(3//2) (2 - (r)/(a_(0))) e^(-r//a_(0)) , where a_(0) is Bohr's radius . If the radial node in 2s be at r_(0) , then r_(0) would be equal to :

GRB PUBLICATION-ATOMIC STRUCTURE-Schrodinger Wave equation
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