The hydrate salt `Na_2 CO_3.xH_2O` undergoes `63%`loss in mass on heating and becomes anhydrous. The value of `x` is :

The hydrated salt Na_(2)CO_(3).xH_(2)O undergoes 63% loss in mass on heating and becomes anhydrous . The value x is :

The hydrated salt Na_2 SO_4. nH_2 O undergoes 56% loss in mass on heating and becomes anhydrous. The value of 'n' will be :

The hydrated salt Na_(2)SO_(4).xH_(2)O undergoes 55% loss in weight on heating and becomes anhydrous. The value of x will be

The term mole first used by Ostwald in 1896 refers for the ratio of mass of a substance in g and its molecular weight. 1 "mole" of a gaseous compound occupies 22.4 "litre" at NTP and contains 6.023xx10^(23) molecules of gas. The hydrated salt Na_(2)SO_(4).nH_(2)O undergoes 56% loss in weight on heating and becomes anhydrous. The value of n will be:

The hydrated salt, Na_(2)SO_(4)*nH_(2)O undergoes 55.9% loss in weight on heating and becomes anhydrous. The value of n will be:

The value of x, if hydrated salt A_(2)SO_(4).xH_(2)O undergoes 45% loss in mass on heating and becomes anhydrous, is: (where atomic weight of A is 7).

The crystalline salt Na_(2)CO_(3)*xH_(2)O on heating loses "63%" of its mass and becomes anhydrous.The formula of the compound is "