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0.05 mole of LiAlH(4) in ether solution ...

0.05 mole of `LiAlH_(4)` in ether solution was placed in a flask containing 74g (1 mole) of t-butyl alcohol. The product `LiAlHC_(12)H_(27)O_(3)` weighed 12.6 g. If Li atoms are conserved, the percentage yield is:
[Li = 7, Al = 27, H=1, C=12, O=16]

A

0.25

B

0.75

C

1

D

0.15

Text Solution

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The correct Answer is:
C
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