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An oleum sample is labelled as 113.5%. I...

An oleum sample is labelled as 113.5`%`. Identity the incorrect statement

A

The amount of free `SO_(2)` in 50g oleum sample is 30 g

B

The amount of `H_(2)SO_(4)` in 50g oleum sample is 30g

C

The new labelling of oleum sample when 8 g water is added in 100 g original oleum sample is `(100+(137.5)/(27))%`

D

In the original 50g oleum sample when 6.75 g is added then 56.75g `H_(2)SO_(4)` is produced.

Text Solution

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The correct Answer is:
B
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