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H(2)O(2) solution of 45.4 V at STP . In ...

`H_(2)O_(2)` solution of 45.4 V at STP . In a hospital of Kota, patient under artifical respiration take s200ml `O_(2)` per min at 1 atm and 273 K and a cylinder last for 2.8 hours . After that it cannot be used for respiration though it still contains `H_(2)O_(2)` .
[Assume volume of solution and rate of decomposition remain constant]
Initial moles of `H_(2)O_(2)` in a cylinder are:

A

12

B

16

C

8

D

24

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The correct Answer is:
A
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H_(2)O_(2) solution of 45.4 V at STP . In a hospital of Kota, patient under artifical respiration take s200ml O_(2) per min at 1 atm and 273 K and a cylinder last for 2.8 hours . After that it cannot be used for respiration though it still contains H_(2)O_(2) . [Assume volume of solution and rate of decomposition remain constant] Volume of oxygen used for respiration is :

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GRB PUBLICATION-MOLE CONCEPT, STOICHIOMETRY & CONCENTRATION TERMS-Comprehension#67
  1. H(2)O(2) solution of 45.4 V at STP . In a hospital of Kota, patient un...

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