Home
Class 11
CHEMISTRY
H(2)O(2) solution of 45.4 V at STP . In ...

`H_(2)O_(2)` solution of 45.4 V at STP . In a hospital of Kota, patient under artifical respiration take s200ml `O_(2)` per min at 1 atm and 273 K and a cylinder last for 2.8 hours . After that it cannot be used for respiration though it still contains `H_(2)O_(2)` .
[Assume volume of solution and rate of decomposition remain constant]
Initial moles of `H_(2)O_(2)` in a cylinder are:

A

12

B

16

C

8

D

24

Text Solution

Verified by Experts

The correct Answer is:
A
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • MOLE CONCEPT, STOICHIOMETRY & CONCENTRATION TERMS

    GRB PUBLICATION|Exercise Comprehension#68|1 Videos
  • MOLE CONCEPT, STOICHIOMETRY & CONCENTRATION TERMS

    GRB PUBLICATION|Exercise Comprehension#69|1 Videos
  • MOLE CONCEPT, STOICHIOMETRY & CONCENTRATION TERMS

    GRB PUBLICATION|Exercise Comprehension#66|1 Videos
  • ISOMERISM

    GRB PUBLICATION|Exercise SUBJECTIVE TYPE|67 Videos
  • NOMENCLATURE AND CLASSIFICATION

    GRB PUBLICATION|Exercise Subjective Type|24 Videos

Similar Questions

Explore conceptually related problems

500 ml of a H_(2)O_(2) solution on complete decomposition produces 2 moles of H_(2)O . Calculate the volume strength of H_(2)O_(2) solution ?

17g of H_(2)O_(2) is present in 100ml of an aqueous solution. 10ml of this solution on decomposition at S.T.P will produce ml of O_(2) at S.T.P

Knowledge Check

  • H_(2)O_(2) solution of 45.4 V at STP . In a hospital of Kota, patient under artifical respiration take s200ml O_(2) per min at 1 atm and 273 K and a cylinder last for 2.8 hours . After that it cannot be used for respiration though it still contains H_(2)O_(2) . [Assume volume of solution and rate of decomposition remain constant] Volume strenght of H_(2)O_(2) left in solution is:

    A
    11.35 V
    B
    22.7 V
    C
    5.67 V
    D
    34.05 V
  • H_(2)O_(2) solution of 45.4 V at STP . In a hospital of Kota, patient under artifical respiration take s200ml O_(2) per min at 1 atm and 273 K and a cylinder last for 2.8 hours . After that it cannot be used for respiration though it still contains H_(2)O_(2) . [Assume volume of solution and rate of decomposition remain constant] Volume of oxygen used for respiration is :

    A
    11.2 L
    B
    22.4 L
    C
    33.6 L
    D
    5.6 L
  • What is the volume of O_(2) liberated at NTP by complete decomposition of 100 mL of 2M solution of H_(2)O_(2) ?

    A
    `22.4 L`
    B
    `2.24 L`
    C
    `0.224L`
    D
    `224L`
  • Similar Questions

    Explore conceptually related problems

    What is the volume of O_(2) liberated at NTP by complete decomposition of 100 mL of 2 M solution of H_(2)O_(2) ?

    The strength of H_(2)O_(2) (in g/l ) in 11.2 volume solution of H_(2)O_(2) is

    The volume strength of the H_(2)O_(2) solution is :

    The strength of H_(2)O_(2) (wg/litre) in 11*2 volume solution of H_(2)O_(2) is

    In a given sample of H_(2)O_(2) each 100 mL of solution contains 68 mg of H_(2)O_(2) . The molarity of the solution is