With what velocity should an `alpha ` paricle travel towards the nucleus of a copper atom so as to arrive at a distance `10^(-13)m` from the nucleus of the copper atom?

Explanation

`(1)/2m_(alpha)v_(alpha)^(2)=(kz_(1)z_(2))/(r_("min")^(2))=(k(2e)k(63e))/r_("min")^(2)`
`v_(alpha)=(k(2e)(63e))/(m_(alpha).r^(2)_("min")`
`v_(alpha)=sqrt((2k.2e.63e)/(m_(alpha).r_("min")^(2)))=6.3xx10^(6)m//s`