(i) What is the energy and wavelenght of phpotons of frequncey 3.4MHz?
(ii) Also calculate the energy per mole of photons of the same wavelength.

Explanation

`v=3.4MHz=3.4xx10^(6)HZ=3.4xx10^(6)s^(-1).`
`lambda=(c)/v=(3xx10^(8)ms^(-1))/(3.4xx10^(6)s^(-1))`=88.2m
Energy, `E=hv=6.626xx10^(-34)xx3.4xx10^(6)J`
=`2.253xx10^(-27)J`
Enegry per mole of photon = `6.02xx10^(23)xx2.53xx10^(-27)J mol^(-1)`
`=1.356xx10^(-3) J mol^(-1)`