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Radiation of lambda=155 nm was irradiate...

Radiation of `lambda`=155 nm was irradiated on Li(work function =5 eV) plante . The stopping potential (in eV) is.

A

4 eV

B

5 eV

C

3 eV

D

1 eV

Text Solution

Verified by Experts

The correct Answer is:
C

`V=(hc)/lambda_(2)-phi_(0)=3 eV`
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BANSAL-ATOMIC STRUCTURE-Exercise.1
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